Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck's constant, h = 6.63 xx 10^(-34)Js, speed of light = 3 xx 10^(8) ms^(-1))

Calculate the energy in joule corresponding to light of wavelength 45

1.	Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck's constant, h = 6.63 xx 10^(-34)Js, speed of light = 3 xx 10^(8) ms^(-1))
Answer» `6.67 XX 10^(15)` `6.67 xx 10^(11)` `4.42 xx 10^(-15)` `4.42 xx 10^(-18)` Solution :`E = hv = (HC)/(lamda)`. Given `lamda = 45 nm = 45 xx 10^(-9) m` `:. E = ((6.63 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/((45 xx 10^(-9) m))` `= 4.42 xx 10^(-18) J`