1.

Calculate the energy in the 2F capacitor.(a) 8.6kJ(b) 64kJ(c) 64J(d) 6.4kJ

Answer» Correct answer is (d) 6.4kJ

To elaborate: From the expression:

WD= CV^2/2 = 2*80^2/2=6400J=6.4kJ.


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