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Calculate the energy in the 5 ohm resistor in 20 seconds.(a) 21.5kJ(b) 2.15kJ(c) 2.15J(d) 21.5kJI got this question in homework.This interesting question is from Energy topic in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

The correct OPTION is (a) 21.5kJ

For explanation I WOULD say: The current in the circuit is equal to the current in the 5 ohm RESISTOR since it a SERIES connected circuit, hence I=220/(5+10)=14.67A. P=I^2R = 14.67^2*5=1075.8W. E=Pt = 1075.8*20 = 21516J=21.5kJ.



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