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Calculate the energy of an electron in the first Bohr orbit of`He^(+)`. |
Answer» `E_(n) = -2.18 xx 10^(-18) ((Z^(2))/(n^(2)))J = - 13.6 (Z^(2))/(n^(2)) eV = 54.4 eV` `Z=2 ` `n=1` `E_(1)= (- 2.18 xx 10^(-18 ) xx ( 2)^(2))/( (1)^(2))` `E_(1) =- 8.72 xx 10^(-18) J` |
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