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Calculate the energy required for the process. He_(g)^(+) rarr He_((g))^(2+) + e^(-) The ionisation energy for the H atom in its ground state is -13.6 eV atom^(-1). |
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Answer» Solution :The ionization energy for the H ATOM in its GROUND state `= -13.6 eV "atom"^(-1)` Ionization energy = `(-13.6)/(n^2) z^2 eV` Z = atomic NUMBER n = PRINCIPLE QUANTUM number or shell number For `He n = 1, Z = 2` I.E = `(-13.6 xx 2^2)/(1^2) eV` I.E of the `He^(2+) = -54.4 eV`. |
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