1.

Calculate the energy required for the process.He_(g)^(+)rarrHe_(g)^(2+)=e^(-)The ionization energy for the H atom in its ground state is -13.6eV atom^(-)

Answer»

SOLUTION :The ionization energy for the H ATOM in Its ground STATE`=13.6eV "atom"^(1)`
Ionization energy`=13.6z^(2)/(n^(2)eV)`
z=atomic number
n=principal quantum number or shell number
For He,n=1,z=2
`I.E.=(-13.6xx2^(2))/(1^(2))eV`
I.E. of`He^(+)` to `He^(2+)`=-54.4eV


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