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Calculate the energy required for the process.He_(g)^(+)rarrHe_(g)^(2+)=e^(-)The ionization energy for the H atom in its ground state is -13.6eV atom^(-) |
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Answer» SOLUTION :The ionization energy for the H ATOM in Its ground STATE`=13.6eV "atom"^(1)` Ionization energy`=13.6z^(2)/(n^(2)eV)` z=atomic number n=principal quantum number or shell number For He,n=1,z=2 `I.E.=(-13.6xx2^(2))/(1^(2))eV` I.E. of`He^(+)` to `He^(2+)`=-54.4eV |
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