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Calculate the energy stored in the condenser the given circuit |
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Answer» Correct Answer - `4 xx 10^(-4)J` Total resistance of arm `ABCD` `R = 2+ 3 + 5 = 10 Omega` Potential difference across `A and D` `V = 1 xx R = 2 xx 10 = 20V` Energy stored in capctor `= (1)/(2) CV^(2)` `= (1)/(2) xx (2 xx 10^(-6)) xx (20)^(2) = 4 xx 10^(-4)J` |
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