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Calculate the enthalpy change for the isomerization reaction as given: CH_(2)=CH-CH_(2)-CH=CH-CH=CH_(2) (A) (NaNH_(4))/(Delta)CH_(2)=CH-CH=CH-CH=CH-CH_(3) (B) "Use the following data": DeltaH_(f)^(@)(C_(2)H_(4))=-2275.5KJ//mol DeltaH_(f)^(@)(C_(2)H_(6))=-2839.2 KJ//mol Resonance energy of A=50Kj/mol Resonance energy of B=70KJ/mol |
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Answer» `-1692.6KJ//mol` |
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