Calculate the enthalpy change for the reaction between CO_(2) and H_(2)O to produce one mole of glucose (C_(6)H_(12)O_(6)) . What wouldbe enthalpy change for the production of 18g of glucose ? The enthalpy of combustion of glucoseis 2840 kJmol^(-1).

Calculate the enthalpy change for the reaction between CO_(2) and H_(2

1.	Calculate the enthalpy change for the reaction between CO_(2) and H_(2)O to produce one mole of glucose (C_(6)H_(12)O_(6)) . What wouldbe enthalpy change for the production of 18g of glucose ? The enthalpy of combustion of glucoseis 2840 kJmol^(-1).
Answer» SOLUTION :Given `: C_(6)H_(12)O_(6)(s) + 6O_(2)(g) rarr 6 CO_(2)(g) + 6H_(2)O(l), DeltaH = - 2849kJ mol^(-1)` Aim `:` Reverse Reaction for which`Delta_(r) H = + 2840 kJ mol^(-1)` This is the enthalpy change for PRODUCTIONOF 1 MOLE ( 180g) of glucose. HENCE, for 18 g glucose, `Delta H = + 284kJ`