Calculate the enthalpy change on freezing of 1.0 mol of water at 10.0°c to ice at -10.0°c. Delta_("fus") H= 6.-03 "kJ mol"^(-1) "at " 0^(@) C C_(p) [H_(2) O_((l)) ]= 75.3 "J mol"^(-1) K C_(p) [H_(2) O_((s))] =36.8 "J mol"^(-1) K

Calculate the enthalpy change on freezing of 1.0 mol of water at 10.0�

1.	Calculate the enthalpy change on freezing of 1.0 mol of water at 10.0°c to ice at -10.0°c. Delta_("fus") H= 6.-03 "kJ mol"^(-1) "at " 0^(@) C C_(p) [H_(2) O_((l)) ]= 75.3 "J mol"^(-1) K C_(p) [H_(2) O_((s))] =36.8 "J mol"^(-1) K
Answer» Solution :`Delta_("FUS") H= 6030 "J/mol"` `DeltaH=C_(p) [H_(2) O_((L)) ] xx Delta T + (Delta H)/( T_(f) ) + C_(p) [H_(2) O _((s)) ] xx Delta T` `= (75.3) (0-10) K + (-6.03) "J mol"^(-1) - 368 "J mol"^(-1)` `=-7151 "J/mol"= -7.151 "kJ/mol"`