Calculate the enthalpy of formation of carbon monoxide (CO) from the following data: (i) C(s) + O(g) rarr CO_(2)(g), Delta_(r)H^(@) = - 393.5 kJ mol^(-1) (ii) CO(g) + (1)/(2) O_(2)(g) rarrCO_(2)(g) , Delta _(r) H^(@) = - 283. 0 kJ mol^(-1)

Calculate the enthalpy of formation of carbon monoxide (CO) from the f

1.	Calculate the enthalpy of formation of carbon monoxide (CO) from the following data: (i) C(s) + O(g) rarr CO_(2)(g), Delta_(r)H^(@) = - 393.5 kJ mol^(-1) (ii) CO(g) + (1)/(2) O_(2)(g) rarrCO_(2)(g) , Delta _(r) H^(@) = - 283. 0 kJ mol^(-1)
Answer» Solution :We AIM at` :C(s) +(1)/(2) O_(2)(g) rarr CO(g) , Delta_(f) H^(@) = ?` Subtracting eqn. (ii) fromeqn. (i), we get `C(s) +(1)/(2) O_(2)(g)- CO(g) rarr0, Delta_(R) H^(@) = - 393.5 - (- 283.0) = - 110.5 KJ mol^(-1)` or `C(s) +(1)/(2) O_(2)(g) rarr CO (g) , Delta _(r) H^(@) = - 110.5 kJ` `:. ` Heat of FORMATION of CO is`: Delta _(f) H^(@) = - 110.5 kJ mol^(-1)`