Calculate the enthalpy of formation of methanol from the following data, CH_(3)OH(l) + (3)/(2)O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(l) ….(i)""Delta H^(@) = -726.4 kJ mol^(-1) C"(graphite)" + O_(2)(g) rarr CO_(2)(g) ….(iii) ""Delta H^(@) = -393.5 kJ mol^(-1) H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(l) ....(iii) ""Delta H^(@) = -285.8 kJ mol^(-1).

Calculate the enthalpy of formation of methanol from the following dat

1.	Calculate the enthalpy of formation of methanol from the following data, CH_(3)OH(l) + (3)/(2)O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(l) ….(i)""Delta H^(@) = -726.4 kJ mol^(-1) C"(graphite)" + O_(2)(g) rarr CO_(2)(g) ….(iii) ""Delta H^(@) = -393.5 kJ mol^(-1) H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(l) ....(iii) ""Delta H^(@) = -285.8 kJ mol^(-1).
Answer» Solution :Required equation, `C "(graphite)" + 2H_(2)(g) + (1)/(2)O_(2)(g) rarr CH_(3)OH(l)` Reverse Eq. (1) MULTIPLY Eq. (3) by 2 and add to Eq. (2) `{:(CO_(2)(g)+2H_(2)O(l) rarr CH_(3)OH(l)+ (3)/(2)O_(2)(g) "" DELTA H^(@) = +726.4 kJ MOL^(-1)),(2H_(2)(g) + O_(2)(g) rarr 2H_(2)O(l) ""Delta H^(@) = -571.6 kJ mol^(-1)),("C(graphite)" + O_(2)(g) rarr CO_(2)(g) ""Delta H^(@) = -393.5 kJ mol^(-1)):}/("C(graphite)" + 2H_(2)(g) + (1)/(2)O_(2)(g) rarr CH_(3)OH(l)Delta H^(@) = -238.5 kJ mol^(-1))` `Delta_(f)H^(@)` of `CH_(3)OH = -238.5 kJ mol^(1)`.