1.

Calculate the enthalpy of formationn of carbon disulphidegiven that the enthalpy of combustion of carbon disulphide is110.2 kJ mol^(-1) and thoseof sulphur and carbon are 297.4 kJ and 394.5 kJ // g atom respectively.

Answer»


Solution :Aim `: C(s)+ 2S(s) rarr CS_(2)(l), DeltaH = ?`
GIVEN `: (i) CS_(2)(l) + 3O_(2)(G) rarr CO_(2)(g) + 2SO_(2)(g), DELTA H- 110.2 kJ mol^(-1)`
(ii)`S(s) + O_(2)(g) rarr SO_(2)(g) , Delta H= - 297.4 kJ mol^(-1)`
(iii) `C(s)+O_(2)(g) rarrCO_(2)(g), Delta H =- 394.5 kJ mol^(-1)`
Eqn. (iii) ` +2 xx ` Eqn. (ii) - Eqn. (i) gives the required result.


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