1.

Calculate the enthalpy of the following reaction : H_(2)C = CH_(2)(g) + H_(2)(g) rarr H_(3)C - CH_(3)(g) Thebond energiesof C-H,C-C,C=C and H-H are 414,347,615 and 435 kJ mol^(-1) respectively

Answer»


ANSWER :`-125kJ MOL^(-1)`


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