Calculate the enthalpyof hydrogenation ofC_(2)H_(2)(g)to C_(2)H_(4)(g). ( Given bond energies:C-H= 414.0 kJ mol^(-1), C=C= 827.6 kJ mol^(-1), C=C= 606 .0 kJ mol^(-1), H-H = 430 .5 kJ mol^(-1))

Calculate the enthalpyof hydrogenation ofC_(2)H_(2)(g)to C_(2)H_(4)(g)

1.	Calculate the enthalpyof hydrogenation ofC_(2)H_(2)(g)to C_(2)H_(4)(g). ( Given bond energies:C-H= 414.0 kJ mol^(-1), C=C= 827.6 kJ mol^(-1), C=C= 606 .0 kJ mol^(-1), H-H = 430 .5 kJ mol^(-1))
Answer» Solution :`H-C-=C-H+H-Hrarr underset(H)underset(\|) overset(H) overset(\|) (C) = underset(H) underset(\|)overset(H) overset(\|) (C) ` `Delta_(r)H^(@)=`B.E. ( REACTANTS) - B.E. ( PRODUCTS ) `=[ B.E.(C-=C) + 2 XX B.E. ( C-H) + B.E. (H-H) ] - [ B.E.(C=C) + 4B.E.(C-H)]` `[827.6+2 xx414.0+ 430 .5]-[606.0 + 4 xx 414.0] = - 175.9 kJ MOL^(-1)`