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Calculate the entropy change during the melting of one mole of ice into water at 0^@C and 1 atm pressure. Enthalpy of fusion of ice is 6008 "J mol"^(-1) . |
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Answer» Solution :`H_(2)O(S)OVERSET(273K)to H_(2)O(l)` `DeltaS_("FUSION")=(DeltaH_("fusion"))/(T_(f))` `= (6008)/(273)` `DeltaS_("fusion")=22.007 J K^(-1)"mole"^(-1)` |
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