1.

Calculate the entropy change during the melting of one mole of ice into water at 0^@C and 1 atm pressure. Enthalpy of fusion of ice is 6008 "J mol"^(-1) .

Answer»

Solution :`H_(2)O(S)OVERSET(273K)to H_(2)O(l)`
`DeltaS_("FUSION")=(DeltaH_("fusion"))/(T_(f))`
`= (6008)/(273)`
`DeltaS_("fusion")=22.007 J K^(-1)"mole"^(-1)`


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