Calculate the entropy change in surroundings when 1.00 mol of H_(2) O_((l)) is formed under standard conditions. Delta_(f)H^( Theta )= -286 "kJ mol"^(-1).

Calculate the entropy change in surroundings when 1.00 mol of H_(2) O_

1.	Calculate the entropy change in surroundings when 1.00 mol of H_(2) O_((l)) is formed under standard conditions. Delta_(f)H^( Theta )= -286 "kJ mol"^(-1).
Answer» SOLUTION :`H_(2(G)) + (1)/(2) to H_(2) O_((l)) ""Delta_(f) H= -286 "kJ/mol" -286 "kJ"` heat is released when ONE mole `H_2 O` formed. So heat is absorbed by surrounding. `q_("surr") = +286 "kJ/mol"` `therefore Delta S= (q_("surr"))/( T) = (286)/( 286)` `= 0.9597 "kJ/mol"= 259.7 "J/K mol"`