Calculate the entropy change in the surrounding when 1.0 mol of H_(2)O(l) is found under standard conditions : Delta_(f)H^(@) = -286 kJ mol^(-1)

Calculate the entropy change in the surrounding when 1.0 mol of H_(2)O

1.	Calculate the entropy change in the surrounding when 1.0 mol of H_(2)O(l) is found under standard conditions : Delta_(f)H^(@) = -286 kJ mol^(-1)
Answer» Solution :`H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(l), Delta_(f)H^(@) = - 286kJ mol^(-1)` This means that when 1 mol of `H_(2)O(l)`, is formed , 286kJof HEAT is released . This heat is absorbed by the surroundings, i.e., `q_(surr)= +286 KJ mol^(-1)` `:. DeltaS =( q_(surr))/(T) = ( 286kJ mol^(-1))/( 298K) = 0.9597kJ K^(-1) mol^(-1)= 959.7 JK^(-1) mol^(-1)`