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Calculate the entropy change of a process H_2 O_((f)) toH_2 O_((g)) at 373K. Enthalpy of vaporization of water is 40850 J Mole""^(-1) |
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Answer» SOLUTION :`H_2 O_((l))toH_2 O` temperature`T =373 K` enthalpyof vapourisationof water =` DELTA H_(vap )= 40580jmol^(-1)` `DeltaS ="entropychange"` ` =( Delta H_(vap))/(T_(b)) = ( 40850 )/( 373 )` ` DeltaS` ( entropychange)` = 109.51 J MOL ^(-1)K^(-1) ` |
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