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Calculate the entropy change of a process H_2 O_((l)) to H_2 O_((g))at 373K. Enthalpy of vapourization of water is 40850 J" Mole"^(-1). |
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Answer» `120 JK^(-1) "mol"^(-1)` Enthalpy of vaporization of water is `=DeltaH = 40850 J "mol"^(-1)` Boiling point = 373 K `= T_b` `DeltaS = (DeltaH)/(T_b) = (40850)/(373) = 109.517` `=109.52 JK^(-1) "mol"^(-1)` |
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