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Calculate the entropy change of a process H_2O_((l)) to H_2O_((g)) at 373K. Enthalpy of vaporization of water is 40850 J "Mole"^(-1) |
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Answer» `120 J K^(-1) "mol"^(-1)` Boiling point =373 K = `T_b` `DELTAS=(DeltaH)/T_b=40850/373` = 109.517 `=109.52 J K^(-1) "mol"^(-1)` |
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