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Calculate the entropy change of a process possessing DeltaH_(t)=2090 J mol^(-1). |
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Answer» Solution :GIVEN : `S_(n(alpha, 13^@C)) oversettolarr S_(n(BETA, 13^@C))` `DeltaH_t="2090 J mol"^(-1) "" DeltaS_t=(DeltaH_t)/T_t` `T_t` =13+273=286 K `DeltaS_t=2090/286` `DeltaS_t=7.307 J K^(-1) "mol"^(-1)` |
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