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Calculate the entropy change of process H_(2)O_((l))rarrH_(2)O_((g)) at 373K. Enthalpy of vaporization of water is 40850"J Mole"^(-1)

Answer»

SOLUTION :`H_2O_((l)) to H_2O_((g))`
TEMPERATURE T=373 K
Enthalpy of vapourisation of WATER =`DeltaH_"vap"=40580 "J mol"^(-1)`
`DeltaS`=entropy CHANGE =`(DeltaH_"vap")/T_b=40850/373`
`DeltaS` (entropy change ) =`109.51 "J mol"^(-1) K^(-1)`


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