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Calculate the entropy change of process H_(2)O_((l))rarrH_(2)O_((g)) at 373K. Enthalpy of vaporization of water is 40850"J Mole"^(-1) |
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Answer» SOLUTION :`H_2O_((l)) to H_2O_((g))` TEMPERATURE T=373 K Enthalpy of vapourisation of WATER =`DeltaH_"vap"=40580 "J mol"^(-1)` `DeltaS`=entropy CHANGE =`(DeltaH_"vap")/T_b=40850/373` `DeltaS` (entropy change ) =`109.51 "J mol"^(-1) K^(-1)` |
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