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Calculate the entropy change when 1 mole of ethanol is evaporated at 351 K. The molar heat of vapourisation of ethanol is 39.84 "kJ mol"^(-1) |
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Answer» Solution :Given : `T_b`=351 K `DeltaH_"VAP"=39840 "J mol"^(-1)` `DeltaS_V`=? `DeltaS_V=(DeltaH_"vap")/T_b` `DeltaS_V=39840/351` `DeltaS_V=113.5 J K^(-1) "mol"^(-1)` |
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