InterviewSolution
Saved Bookmarks
| 1. |
Calculate the equilibrium constant for the reaction `Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), E_(cell)^(@)=0.46 V`.A. `579jK^(-1)`B. `386jK^(-1)`C. `193jK^(-1)`D. None of these. |
|
Answer» Correct Answer - B `DeltaS^(@)=nF((dE^(@))/(dT))_(p)` `=2xx96500((0.48-0.46)/(310-300))` `=(2xx96500xx0.02)/(10)=386JK^(-1)` |
|