1.

Calculate the equilibrium constant for the reaction `Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), E_(cell)^(@)=0.46 V`.A. `579jK^(-1)`B. `386jK^(-1)`C. `193jK^(-1)`D. None of these.

Answer» Correct Answer - B
`DeltaS^(@)=nF((dE^(@))/(dT))_(p)`
`=2xx96500((0.48-0.46)/(310-300))`
`=(2xx96500xx0.02)/(10)=386JK^(-1)`


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