Calculate the equilibrium constant for the reaction at 298 K `Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s)` Given` " " E_(Zn^(2+)//Zn)^(@)=-0.76 V` and `E_(Cu^(2+)//Cu)^(@)=+0.34 V`

Calculate the equilibrium constant for the reaction at 298 K `Zn(s)+Cu

1.	Calculate the equilibrium constant for the reaction at 298 K `Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s)` Given` " " E_(Zn^(2+)//Zn)^(@)=-0.76 V` and `E_(Cu^(2+)//Cu)^(@)=+0.34 V`
Answer» `DeltaG^(@)=-"RT In Kc "=-2.303" RT log Kc"` `therefore" "-212300=-2.303xx8.314xx298xxlog Kc` `"or "log Kc =(212300)/(2.303xx8.314xx298)=37.2074` `Kc" = Antilog "37.2074=1.6xx10^(37)`

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Calculate the equilibrium constant for the reaction at 298 K `Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s)` Given` " " E_(Zn^(2+)//Zn)^(@)=-0.76 V` and `E_(Cu^(2+)//Cu)^(@)=+0.34 V`

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