1.

Calculate the equivalent weight of H_3PO_4 and Ca(OH)_2on the basis of given reaction . H_(3)PO_4 + NaOH to NaH_2PO_4+H_2O Ca(OH)_2+HCI to Ca(OH)CI+H_2O

Answer»

SOLUTION :Equivalent WEIGHT of `H_2PO_4`
`=("Molecular mass")/("No. of replaceable" H^+)=(98)/(2)=49`
Equivalent weight of `Ca(OH)_2`
`=("Molecular mass")/("No. of replacement"OH^-)=(74)/(2)=37`.


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