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Calculate the equivalent weight of H_3PO_4 and Ca(OH)_2on the basis of given reaction . H_(3)PO_4 + NaOH to NaH_2PO_4+H_2O Ca(OH)_2+HCI to Ca(OH)CI+H_2O |
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Answer» SOLUTION :Equivalent WEIGHT of `H_2PO_4` `=("Molecular mass")/("No. of replaceable" H^+)=(98)/(2)=49` Equivalent weight of `Ca(OH)_2` `=("Molecular mass")/("No. of replacement"OH^-)=(74)/(2)=37`. |
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