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Calculate the equivalent weight of KMnO_(4) |
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Answer» Solution :`KMnO_(4)` acts as oxidant in acidic, basic and also in neutral medium. In acidic medium: `KMnO_(4)+8H^(+) +5e^(-) to K^(+) +MN^(2+)+4H_(2)O` One molecular of `KMnO_(4)` gains five electrons. Hence the equivalent WEIGHT of `KMnO_(4):` EQ. `wt=("Mol.wt. of "KMnO_(4))/(5)=(158.04)/(5)=31.608` In neutral as well as weakly basic medium: `KMnO_(4)+2H_(2)O+3e^(-) to K^(+)+4OH^(-)+MnO_(2)` One molecule of `KMnO_(4)` gains three electrons. Eq. wt `=("Mol.wt. of "KMnO_(4))/(3)=(158.04)/(3)=52.68` In strongly alkaline medium `: MnO_(4)+E^(-) to MnO_(4)^(2-)` One molecule of `KMnO_(4)` gains one electron. Eq. wt `=("MOLE. wt. of "KMmO_(4))/(1)=158.04` |
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