1.

Calculate the excess pressure inside a soap bubble of radius 1.0mm. (Given surface tension of soap solution =0.040 Nm^(-1)).

Answer»

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Solution :Given `T=0.040 Nm^(-1)`
`r=1 xx 10^(-3)m`
We KNOW that excess pressure INSIDE SOAP bubble, `P=(4T)/(R)=(4 xx 0.04)/(1 xx 10^(-3))=160Nm^(-2)`


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