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Calculate the excess pressure inside a soap bubble of radius 1.0mm. (Given surface tension of soap solution =0.040 Nm^(-1)). |
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Answer» <P> Solution :Given `T=0.040 Nm^(-1)``r=1 xx 10^(-3)m` We KNOW that excess pressure INSIDE SOAP bubble, `P=(4T)/(R)=(4 xx 0.04)/(1 xx 10^(-3))=160Nm^(-2)` |
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