Calculate the extent of hydrolysis of 0.005M K_(2)CrO_(4) K_(2)=3.1xx10^(7) for H_(2)CrO_(4). (H_(2)CrO_(4) is strong for first ionisation and K_(1) = 1.6).

Calculate the extent of hydrolysis of 0.005M K_(2)CrO_(4) K_(2)=3.1xx1

1.	Calculate the extent of hydrolysis of 0.005M K_(2)CrO_(4) K_(2)=3.1xx10^(7) for H_(2)CrO_(4). (H_(2)CrO_(4) is strong for first ionisation and K_(1) = 1.6).
Answer» ANSWER :`0.253%;`