Calculate the external work done by the system in Kcal, when 40kCal of heat is supplied to the system, 8400 J of internal work is done.

Calculate the external work done by the system in Kcal, when 40kCal of

1.	Calculate the external work done by the system in Kcal, when 40kCal of heat is supplied to the system, 8400 J of internal work is done.
Answer» Solution :Heat supplied to the system at CONSTANT pressure = change in internal ENERGY + External WORK done The change in internal energy = Internal work done= `8400J=8400/4200` KCAL = 2 KCal. `:. 40 KCal = 2 kCal` + External work done The external work done = `40-2=38 kCal `