1.

Calculate the external work done by the system in kCal, when 40 k Cal of theat is supplied to the system, 8400 J of internal work is done.

Answer»

Solution :Heat SUPPLIED to the SYSTEM at constant pressure = change in internal energy + External work DONE.
The change in internal energy = Internal work done
`=8400 J = (8400)/(4200) kCal = 2kCal`
`:.40kCal=2kCal+` External work done.
The external work done `=40-2=38`kCal


Discussion

No Comment Found