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Calculate the external work done by the system in kCal, when 40 k Cal of theat is supplied to the system, 8400 J of internal work is done. |
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Answer» Solution :Heat SUPPLIED to the SYSTEM at constant pressure = change in internal energy + External work DONE. The change in internal energy = Internal work done `=8400 J = (8400)/(4200) kCal = 2kCal` `:.40kCal=2kCal+` External work done. The external work done `=40-2=38`kCal |
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