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Calculate the following upto proper significant figures : (i) 45.95 xx 0.061, (ii) 312.6 xx 14.68 (iii) 3.2 + 4.004, (iv) 515.69-312.812 (v) (6.7 xx 0.00421)/(11.8), (vi) (5.4 xx 10^(-3) xx 0.0649)/(3.11 xx 10^(-2)) |
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Answer» Solution :(i) In this calculation, the first quantity is more precise and consists of four significant figures while the second quantity is less precise and consists of only two significant figures. Therefore, the result should be reported upto two significant figures only. Therefore, `45.95 XX 0.061 = 2.80295 - 2.8` ANS. (ii) In this calculation, both the quantities contain four significant figures. Hence, the result should be reported upto four significant figures. Therefore, `312.614.68 = 21.294277 = 21.29`Ans. (iii) In this addition, the first number has one DECIMAL place while the second number has three decimal places. Hence, the result should be reported only upto one decimal place. Therefore, `3.2 + 4.004 = 7.204 = 7.2` Ans. (iv) In this subtraction, the first number has two decimal places while the second one has three decimal places. Therefore, the result should be reported only upto two decimal places. Hence, `515.69 - 312.812 = 202.878 = 202.88` Ans. (v) In this calculation, the least precise number, i.e., 6.7 consists of only two significant figures. Therefore, the result should be EXPRESSED only upto two significant figures. Hence, `(6.7 xx 0.00421)/(11.8) = 2.39042 xx 10^(-3) = 2.4 xx 10^(-3)` (after rounding off) Ans. (VI) In this calculation, the least precise number, i.e.,`5.4xx10^(-3)`consistsof onlytwosignificant figures. Hence, the result should be reported upto two significant figures only. Therefore, `(5.4 xx 10^(-3) xx 0.0649)/(3.11 xx 10^(-2)) = 1.12688 xx 10^(-2) = 1.1 xx 10^(-2)` |
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