1.

Calculate the force .F. needed to punch a 1.46 cm diameter hole in a steel plate 1.27 cm thick (as shown in fig). The ultimate shear strength of steel is 345 M N//m^(2)

Answer»

Solution : As in punching, SHEAR elasticity is involved, the hole will be punched it
`((F_(11))/(A)) gt` ultimate shears streass `: F_(11) gt` (shear STRESS) X Area
`F_(11) min=(3.45xx10^(8)) (2PI RL)(A=2pi rL)`
`=(3.45xx10^(8))(2xx3.14)xx0.73xx10^(-2)xx1.27xx10^(-2)~~200 KN`


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