Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms^(-2). The force of friction per quintal is 0.5 N.

Calculate the force required to move a train of 2000 quintal up on an

1.	Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms^(-2). The force of friction per quintal is 0.5 N.
Answer» <html><body><p></p>Solution :Force of friction = 0.5 N per <a href="https://interviewquestions.tuteehub.com/tag/quintal-611642" style="font-weight:bold;" target="_blank" title="Click to know more about QUINTAL">QUINTAL</a> <br/>`f = 0.5 xx 2000= 1000`per quintal <br/>m = 2000 quintals =` 2000 xx 100` kg <br/>` sin theta = 1/50 , a=2m//s^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/>In <a href="https://interviewquestions.tuteehub.com/tag/moving-548882" style="font-weight:bold;" target="_blank" title="Click to know more about MOVING">MOVING</a> up an inclined <a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a>, force <a href="https://interviewquestions.tuteehub.com/tag/required-1185621" style="font-weight:bold;" target="_blank" title="Click to know more about REQUIRED">REQUIRED</a> against gravity <br/>`= mg sin theta= 39200N` <br/>And force required to produce acceleration = ma. <br/>` = 2000 xx 100 xx 2 = 40,0000 N` <br/>Total force required = 1000+ 39,200 + 40,0000 = 440200 N.</body></html>