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Calculate the formula weight of each of the following to three significant figures, using a table of atomic weight (AW): (a) chloroform CHCl_3 (b)Iron (III) sulfate , Fe_2(SO_4)_3. |
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Answer» Solution :a. ` 1 xx AW` or C = 12.0 amu `1 xx AW ` of H = 1.0 amu ` 3 xx AW` of Cl `=3 xx 35.45`= `UL(106.4 " amu")` Formula WEIGHT of `CHCl_3`= `ul(119.4 " amu ")` The ansser rounded to three significant figure is 119 amu. b. IRON (III) SULFATE ` 2 xx `Atomic weight of Fe `=2 xx 55.8`=111.6 am ` 3 xx ` Atomic weight of O `= 12 xx 16 = ul(192.0" amu ")` The answer rounded to three significant figure is ` 4.00 xx 10^(2) ` amu. |
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