1.

Calculate the fractional charge on each atom in HBr molecule. Given that Dipole moment of BHr = 0 . 78 D,Bond distance of HBr =1.41Å. Electronic charge , e =4. 8 xx 10^(-10) esu

Answer»


Solution :Suppose PARTIAL CHARGE on H = + q . Then partial chargeon Br = - q
Diplo moment` (MU) = q xx d orq = (mu)/(d) =(0.78xx10^(-18) "esu cm")/(4.8xx10^(-8)cm) = 0.55xx10^(-10) esu`
Fractional charge`(delta) = (q)/(E) = (0.55xx10^(_10)esu)/(4.8xx10^(-10)esu) = 0 .11thereforedelta_(H^+)= 0.11,delta_(Br^-) = - 0.11`.


Discussion

No Comment Found