1.

Calculate the fractional charge on each atom of HBr. The dipole moment of HBr is 0.78D and its bond length is 1.41Å. [electronic charge, e=4.8xx10^(-10) esu, 1D=10^(-10)esu*cm].

Answer»

SOLUTION :Dipole moment, `mu=qxxd`
or, `Q=(mu)/(d)=(0.78xx10^(18)esu*cm)/(1.41xx10^(-8)cm)=0.55xx10^(-10)esu`
Fraction of charge `(delta)=("Charge present (q)")/("Electronic charge (e)")`
`=(0.55xx10^(-10)esu)/(4.8xx10^(-10)esu)=0.11`
`therefore`The fractional charge on HYDROGEN, `delta_(H^(+))=0.11 ` and the fractional charge on BROMINE,
`delta_(Br)=-0.11`


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