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Calculate the fractional charge on each atom of HBr. The dipole moment of HBr is 0.78D and its bond length is 1.41Å. [electronic charge, e=4.8xx10^(-10) esu, 1D=10^(-10)esu*cm]. |
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Answer» SOLUTION :Dipole moment, `mu=qxxd` or, `Q=(mu)/(d)=(0.78xx10^(18)esu*cm)/(1.41xx10^(-8)cm)=0.55xx10^(-10)esu` Fraction of charge `(delta)=("Charge present (q)")/("Electronic charge (e)")` `=(0.55xx10^(-10)esu)/(4.8xx10^(-10)esu)=0.11` `therefore`The fractional charge on HYDROGEN, `delta_(H^(+))=0.11 ` and the fractional charge on BROMINE, `delta_(Br)=-0.11` |
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