Calculate the free energy change in kJ when 1 mole of NaCl is dissolved in water at 298 K, Given a) U of NaCl (U = lattice energy) = 778 kJ "mole"^(-1) b) Hydration energy of NaCl = -774.3 kJ "mole"^(-1) (c) Entropy change at 298K = 43 "mole"^(-1)

Calculate the free energy change in kJ when 1 mole of NaCl is dissolve

1.	Calculate the free energy change in kJ when 1 mole of NaCl is dissolved in water at 298 K, Given a) U of NaCl (U = lattice energy) = 778 kJ "mole"^(-1) b) Hydration energy of NaCl = -774.3 kJ "mole"^(-1) (c) Entropy change at 298K = 43 "mole"^(-1)
Answer» SOLUTION :`DELTA H` of solution of NaCl= Lattice energy of NaCl- HYDRATION energy of NaCl `Delta G= Delta H - T Delta S= - 9`