Calculate the free energy change per mole for the following reactions. (1) CaCO,(s) + CaO(s) + CO,(g) 298K V AH = 1179 kJ, AS = 160,43K-

Calculate the free energy change per mole for the following reactions.

1.	Calculate the free energy change per mole for the following reactions. (1) CaCO,(s) + CaO(s) + CO,(g) 298K V AH = 1179 kJ, AS = 160,43K-
Answer» The Gibbs free energy change of the reaction is -130.1 kJ and the reaction is spontaneous in nature.Explanation:For the given chemical EQUATION:CaCO3 + CaO+CO(9)To calculate the Gibbs free energy of the reaction, we use the equation:AGAH-TASwhere,AH = enthalpy change = +177.9 kJ = 177900 J (Conversion factor: 1 kJ = 1000 J)T = Temperature = 298 KAS = entropy of the reaction = -160.4 J/KPutting values in above equation, we GET:AG 177900J (298K × (-160.4J/K))AG = -130100.8J = -130.1kJFor a reaction to be spontaneous, the Gibbs free energy of the reaction must be negative.#BrainLock.