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Calculate the freezing point of an aqueous solution containing `10.5g` of Magnesium bromide in 200 g of water, assuming complete dissociation of Magnesium bromide. (Molar mass of magnesium bromide `=184 g mol ^(-1)`, for water `=1.86K kg mol^(-)`). |
Answer» `MgBr_2to Mg^(2+)+2Br^(-)` Complete dissociation. Hence `i=3` `W_8=10.5g` `W_(A)=200g` `K_f=1.86g kg//mol` `M_B=184g//mol` `Delta =ixxK_(f)xx(W_(B))/(M_(B)xxW_(A)(Kg))` `T_(A)^(0)-T_(S)=(3xxoverset(0.93)cancel1.86xx10.5xxoverset(cancel5)cancel1000)/(184xxcancel200xxcancelunderset(2)(10))` `Delta T_(f)=0.15K` `T_(S)=T_(A)^(0)-0.15=273.15-0.15` `T_(S)=273K` |
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