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Calculate the frequency and energy of a photon of radiation having wavelength `6000 Å` |
Answer» Frequency `v = (c)/(lamda)` Substituting `c = 3 xx 10^(8) m s^(-1), lamda = 6000 Å= 6000 xx 10^(-10) m`, we get `v = (3 xx 10^(8) ms^(-1))/(6000 xx 10^(-10)m) = 5 xx 10^(4) s^(-1)` (ii) Energy of the photon E = hv Substituting `h = 6.625 xx 10^(-34) J s, v = 5 xx 10^(14) s^(-1)`, we get `E = 6.625 xx 10^(-34) J s xx 5 xx 10^(14) s^(-1) = 3.3125 xx 10^(-19) J` |
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