1.

Calculate the frequency and energy of a photon of radiation having wavelength `6000 Å`

Answer» Frequency `v = (c)/(lamda)`
Substituting `c = 3 xx 10^(8) m s^(-1), lamda = 6000 Å= 6000 xx 10^(-10) m`, we get
`v = (3 xx 10^(8) ms^(-1))/(6000 xx 10^(-10)m) = 5 xx 10^(4) s^(-1)`
(ii) Energy of the photon E = hv
Substituting `h = 6.625 xx 10^(-34) J s, v = 5 xx 10^(14) s^(-1)`, we get
`E = 6.625 xx 10^(-34) J s xx 5 xx 10^(14) s^(-1) = 3.3125 xx 10^(-19) J`


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