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Calculate the frequency, wave number and energy associated with photon of radiations having wavelength 6000 Ã… . |
Answer» Wavelength `(lambda)=6000 Ã…= 6000 xx 10^(-10)m=6 xx 10^(-7)m` Frequency (v) `=(c)/(lambda) =((3xx 10^(8)ms^(-1)))/((6xx 10^(-7)m))=5 xx 10^(14)s^(-1)` Wave number `(bar(v))=(1)/(lambda)=(1)/((6xx10^(-7)m))=1.6 xx 10^(6)m^(-1)` Energy (E) `=hv=(6.626 xx 10^(-34)Js)xx (5xx10^(14)s^(-1))=33.1 xx 10^(-20)J`. |
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