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Calculate the fundamental frequency of an air column in a tube of length 25 cm closed at one end, if the speed of sound in air is 350 m/s. |
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Answer» v = 350 m/s, L = 25 cm = 0.25 m ∴ The fundamental frequency of the air column is n = \(\frac v{4L}\) = \(\frac{350}{4 \times 0.25}\) = 350 Hz |
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