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Calculate the grams of copper sulphate `(CuSO_(4))` needed to prepare `250.0 mL` of `1.00M CuSO_(4)` ?. |
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Answer» Moles of `CuSO_(4) = M xx V = 1 xx (250)/(1000)` Molar mass of copper sulphate = 159.6 g/mol Hence Mass of copper sulphate (gm) = Moles of `CuSO_(4) xx` Molar mass of copper sulphate `= 1 xx (250)/(1000) xx 159.6 g//mol` = 39.9 gm of Copper sulphate |
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