Calculate the `[H^(o+)]` and `[overset(Theta)OH]` of `0.0315g` of `HNO_(3)` in `500 mL` of water. Calculate `pH` and `pOH` also.

Calculate the `[H^(o+)]` and `[overset(Theta)OH]` of `0.0315g` of `HNO

1.	Calculate the `[H^(o+)]` and `[overset(Theta)OH]` of `0.0315g` of `HNO_(3)` in `500 mL` of water. Calculate `pH` and `pOH` also.
Answer» Correct Answer - A::C `(Mw_(2)` of `HNO_(3) = 53 g mol^(-1))` `M_(HNO_(3)) = (W_(2) xx 1000)/(Mw_(2) xx "vol of sol. In mL")` `= (0.0315 xx 1000)/(63xx500) = 0.001= 10^(-3)M`. `[H^(o+)] = 10^(-3)M,pH = 3` `[overset(Theta)OH] = (K_(w))/([H^(o+)]) = (10^(-14))/(10^(-3)) = 10^(-11)M` `pOH = 11`.

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Calculate the `[H^(o+)]` and `[overset(Theta)OH]` of `0.0315g` of `HNO_(3)` in `500 mL` of water. Calculate `pH` and `pOH` also.

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