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Calculate the heat of formation of KOH from the following data K_((s)) + H_(2)O + aq rarr KOH_((aq)) + (1)/(2) H_(2(g)) , Delta H = -48.4 K.Cal H_(2(g)) + (1)/(2) O_(2(g)) rarr H_(2)O_((l)) , Delta H = -68.44 K.Cal KOH_((s)) + aq rarr KOH_(aq) , DeltaH = -14.01 K.Cal |
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Answer» `+102.83` |
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