1.

Calculate the heat of glucose and its calorific value from following data : (i)C_"(graphite)"+O_(2(g)) to CO_(2(g)) ,DeltaH=-395 KJ (ii)H_(2(g)) +1//2O_2 to H_2O_((l)) , DeltaH=-269.4 KJ (iii)6C+6H_(2(g)) +3O_(2(g)) to C_6H_12O_(6(s)) , DeltaH=-1169.8 KJ

Answer»

Solution :The required equation is
`C_(6)H_(12)O_(6_((s)))+6O_(2_((g)))rarr6CO_(2_((g)))+6H_(2)O_((L))`
(i) `C_("graphite")+O_(2_((g)))rarrCO_(2_((g))):DeltaH=-395.0KJ`
(II) `H_(2_((g)))+1/2O_(2)rarrH_(2)O_((l)):DeltaH=-269.4KJ.`
(III) `6C_("graphite")+6H_(2_((g)))+3_(2_((g)))rarrC_(6)H_(12)O_(6_((s))) : DeltaH=-1169.8KJ.`
MULTIPLY equation (i) and (ii) by 6 and add them up
`C_(6)H_(12)O_(6_((s)))+6O_(2_((g)))rarr6CO_(2_((g)))+6H_(2)O_((l)) DeltaH=-2816.6KJ.`
`:.` Enthalpy of combustion of glucose `=-2816.6KJ.`


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