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Calculate the heat of glucose and its calorific value from following data : (i)C_"(graphite)"+O_(2(g)) to CO_(2(g)) ,DeltaH=-395 KJ (ii)H_(2(g)) +1//2O_2 to H_2O_((l)) , DeltaH=-269.4 KJ (iii)6C+6H_(2(g)) +3O_(2(g)) to C_6H_12O_(6(s)) , DeltaH=-1169.8 KJ |
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Answer» Solution :The required equation is `C_(6)H_(12)O_(6_((s)))+6O_(2_((g)))rarr6CO_(2_((g)))+6H_(2)O_((L))` (i) `C_("graphite")+O_(2_((g)))rarrCO_(2_((g))):DeltaH=-395.0KJ` (II) `H_(2_((g)))+1/2O_(2)rarrH_(2)O_((l)):DeltaH=-269.4KJ.` (III) `6C_("graphite")+6H_(2_((g)))+3_(2_((g)))rarrC_(6)H_(12)O_(6_((s))) : DeltaH=-1169.8KJ.` MULTIPLY equation (i) and (ii) by 6 and add them up `C_(6)H_(12)O_(6_((s)))+6O_(2_((g)))rarr6CO_(2_((g)))+6H_(2)O_((l)) DeltaH=-2816.6KJ.` `:.` Enthalpy of combustion of glucose `=-2816.6KJ.` |
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