Calculate the heat released when 0.5 moles of the nitric acid solution

1.	Calculate the heat released when 0.5 moles of the nitric acid solution is mixed with 0.2 moles of potassium hydroxide solution.
Answer» The heat of neutralization of strong acid and strong base is 57.0 KJ/mol. The rest released when 0.5 moles at the nitric acid solution mixed with 0.2 moles of potassium hydroxide solution. HNO₃ and KOH are strong acid and strong base respectively. 0.2 mole KOH neutralized only 0.2 moles of HNO₃ 0.3 mole HNO₃remain unreacted. \(\because\) Heat of neutralization of strong acid and strong base is = 57.0 KJ/mol. Heat released on neutralization of 0.2 mol HNO₃ and 0.2 mol KOH = 57.0 KJ/mol x 0.2 mol = 11.4 KJ Hence, heat released = 11.4 KJ.

Calculate the heat released when 0.5 moles of the nitric acid solution is mixed with 0.2 moles of potassium hydroxide solution.

Answer»

The heat of neutralization of strong acid and strong base is 57.0 KJ/mol. The rest released when 0.5 moles at the nitric acid solution mixed with 0.2 moles of potassium hydroxide solution.

HNO₃ and KOH are strong acid and strong base respectively.

0.2 mole KOH neutralized only 0.2 moles of HNO₃

0.3 mole HNO₃remain unreacted.

\(\because\) Heat of neutralization of strong acid and strong base is = 57.0 KJ/mol.

Heat released on neutralization of 0.2 mol HNO₃ and 0.2 mol KOH = 57.0 KJ/mol x 0.2 mol

= 11.4 KJ

Hence, heat released = 11.4 KJ.

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