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Calculate the height to which water will rise in a capillary tube of diameter `1xx10^(-3)`m [given surface tension of water is `0.072Nm^(-1)` angle of contact is `0^(@),g=9.8ms^(-2)` and density of water `=1000kgm^(-3)`] |
Answer» Height of capillar rise `h=(2Tcostheta)/(r rhog)=(2xx0.072xxcos0^(0))/(5xx10^(-4)xx1000xx9.8)m=2.94xx10^(-2)m` | |